A treatment is administered to a sample of n = 9 individuals selected from a population with a mean of µ = 80 and a standard deviation of σ = 12. After treatment, the effect size is measured by computing Cohen’s d, and a value of d = 0.50 is obtained. Based on this information, what is the mean for the treated sample??(A) M = 82(B) This cannot be answered without knowing the sample size.(C) M = 6(D) M = 86
Accepted Solution
A:
Answer:a) M =82Step-by-step explanation:Let´s study this as a Normal distribution.As we know in a normal distribution the z score is = (X-μ)/(sd/sqrt(n))where X = mean for the taken sample = What we want to know in this problemμ = Total population mean =80sd= standard deviation= 12n = sample size=9So in this case z=( X-80)/(12/sqr(9))= (X-80)/4also we know that the effect size taken by the machine is 0.5, which is the same as the z-scoreso...0.5 = (X-80)/4 => 0.5*4 = X-80 2+80 = XX = 82