Q:

Write an equation in slope-intercept form for the line that passes through the given point and is parallel to the graph of the given equation (-1,-2),3x-y=4

Accepted Solution

A:
Answer:[tex]y = 3x + 1[/tex]Step-by-step explanation:First, turn [tex]3x - y = 4[/tex] around into Slope-Intercept Form:3x - y = 4-3x - 3x________βˆ’y = βˆ’3x + 4[tex]y = 3x - 4[/tex]The rate of change [slope] is 3:βˆ’2 = 3[βˆ’1] + b βˆ’31 = b[tex]y = 3x + 1[/tex]* Parallel lines have SIMILAR RATE OF CHANGES [SLOPES], so 3 remains the way it is.I am joyous to assist you anytime.