Q:

A poll conducted in 2013 found that 52% of U.S. adult Twitter users get at least some news on Twitter.40. The standard error for this estimate was 2.4%, and a normal distribution may be used to model the sample proportion. Construct a 99% confidence interval for the fraction of U.S. adult Twitter users who get some news on Twitter, and interpret the confidence interval in context.

Accepted Solution

A:
Answer:  (0.458,0.582)Step-by-step explanation:Given : Sample size : [tex]n=815[/tex]The proportion of U.S. adult Twitter users get at least some news on Twitter. : [tex]p=0.52[/tex]Standard error : [tex]s.=0.024[/tex]Significance level : [tex]\alpha: 1-0.99=0.01[/tex]Critical value : [tex]z_{\alpha/2}=2.576[/tex]The confidence interval for population proportion is given by :-[tex]p\pm\ z_{\alpha/2}\ s\\\\=0.52\pm(2.576)(0.024)\\\\\approx0.52\pm0.062=(0.52-0.062,0.52+0.062)=(0.458,0.582)[/tex]Hence, the 99% confidence interval for the fraction of U.S. adult Twitter users who get some news on Twitter, and interpret the confidence interval in context= (0.458,0.582)