At a certain fast-food restaurant, 65% of customers order a chicken sandwich, 44% of customers order french fries, and 76% of customers order a chicken sandwich or french fries (or both items). What is the probability that a randomly selected customer will order both a chicken sandwich and french fries? Write your answer as a decimal (not as a percentage). (If necessary, consult a list of formulas.)

Answer: 0.33Step-by-step explanation:Let C be the event of ordering  chicken sandwich.F be the event of ordering french fries.As per given , we haveP(C)=0.65P(F)=0.44P(C∩F)=0.76Formula we use here, [tex]P(A\cap B)=P(A)+P(B)-P(A\cup B)[/tex]Then, For given situation, we have [tex]P(C\cap F)=P(C)+P(F)-P(C\cup F)[/tex]i.e.  [tex]P(C\cap F)=0.65+0.44-0.76=0.33[/tex]Hence, the probability that a randomly selected customer will order both a chicken sandwich and french fries=0.33